(c^2-6c)+(7c+5)=

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Solution for (c^2-6c)+(7c+5)= equation:


Simplifying
(c2 + -6c) + (7c + 5) = 0

Reorder the terms:
(-6c + c2) + (7c + 5) = 0

Remove parenthesis around (-6c + c2)
-6c + c2 + (7c + 5) = 0

Reorder the terms:
-6c + c2 + (5 + 7c) = 0

Remove parenthesis around (5 + 7c)
-6c + c2 + 5 + 7c = 0

Reorder the terms:
5 + -6c + 7c + c2 = 0

Combine like terms: -6c + 7c = 1c
5 + 1c + c2 = 0

Solving
5 + 1c + c2 = 0

Solving for variable 'c'.

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 1c + -5 + c2 = 0 + -5

Reorder the terms:
5 + -5 + 1c + c2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 1c + c2 = 0 + -5
1c + c2 = 0 + -5

Combine like terms: 0 + -5 = -5
1c + c2 = -5

The c term is 1c.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
c + 0.25 + c2 = -5 + 0.25

Reorder the terms:
0.25 + c + c2 = -5 + 0.25

Combine like terms: -5 + 0.25 = -4.75
0.25 + c + c2 = -4.75

Factor a perfect square on the left side:
(c + 0.5)(c + 0.5) = -4.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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